Stoke's Theorem
Our goal for the rest of this chapter is to generalize Green's
theorem into several different contexts. Indeed, we will conclude with a
very general statement of the fundamental theorem of calculus. We begin by
generalizing Green's theorem to arbitrary surfaces, which is known as Stoke's theorem.
To begin with, suppose that F =
á M,N,P
ñ is
a vector field through a surface r( u,v) =
áx( u,v) ,y( u,v) ,z( u,v)
ñ
which maps a region S in the uv-plane to a surface S in R3.
Also, let's assume that the boundary of S is mapped to the boundary of S.
In addition, we require that ¶S has a counterclockwise
orientation with respect to the unit surface normal n. This
allows us to extend Green's theorem to the following:
Stoke's Theorem: If F =
á M,N,P
ñ
where M,N, and P are differentiable on a simply-connected region
containing S, then
ó õ
|
ó õ
|
S |
curl( F) ·dS = |  |
¶S
|
F·dr |
|
That is, the flux of the curl of F through S is
equal to the circulation of F around ¶S (recall
that circulation is total work along a closed curve). A proof of Stoke's
theorem is included at the end of this section.
EXAMPLE 1 Find the flux of curl( F) through the paraboloid
r( u,v) =
á ucos( v), usin( v) ,1-u2
ñ , u in [ 0,1] , v in [ 0,2p] |
|
when F =
á -y,x,z
ñ , first by direct
evaluation and then by Stoke's theorem.
Solution: First, it is straightforward to show that curl( F) =
á 0,0,2
ñ . Moreover, ru =
á cos( v) ,sin( v),-2u
ñ and rv =
á -usin( v),ucos( v) ,0
ñ , so that
dS = ( ru×rv)
du dv =
á 2u2cosv,2u2sinv,u
ñ du dv |
|
Thus, the flux of the curl by direct evaluation yields
|
|
| |
|
|
ó õ
|
1
0
|
|
ó õ
|
2p
0
|
á 0,0,2
ñ ·
á 2u2cosv,2u2sinv,u
ñ dudv |
| |
|
| |
|
|
|
Alternatively, Stoke's theorem with F(x,y,z) =
á -y,x,z
ñ reduces to
|
|
|  |
¶S
|
F·dr |
| |
|
|  |
¶S
|
á -y,x,z
ñ ·
á dx,dy,dz
ñ |
| |
|
|  |
¶S
|
-ydx+xdy+zdz |
|
|
However, the boundary ¶S of the paraboloid is the unit
circle (see above), which can be parameterized by r( t) =
á cos( t) ,sin( t) ,0
ñ , t in [ 0,2p] . Thus, x = cos( t) , y = sin(t), and z = 0 yields
|
|
|  |
unit circle
|
-ydx + xdy |
| |
|
|
ó õ
|
2p
0
|
|
æ è
|
-y |
dx
dt
|
+x |
dy
dt
|
+0 |
ö ø
|
dt |
| |
|
|
ó õ
|
2p
0
|
sin( t) sin( t) +cos(t) cos( t) dt |
| |
|
| |
|
|
|
Check your Reading: How is
á 0,0,2
ñ
related to
á -y, x, z
ñ in example 1?