Conic Sections   

A conic section is the curve formed by the intersection of a plane with the right circular cone x2+y2 = z2. For example, the plane in the conic explorer below is given by z = p+ex, where p is the parameter of the conic and e > 0 is its eccentricity.  If e = 0, then the conic is a circle. If 0 < e < 1, then the conic is an ellipse. If e = 1, then the conic is a parabola, and if e > 1, then the conic is a hyperbola (click here to open applet in a new window).

 

Parameter: p = uvaEccentricity: ε = jac
LiveGraphics3d Applet
Click and drag the red points to create conic sections.

In cylindrical coordinates, the plane is given by z = p+ercos( q) and the cone is given by r2 = z2. As a result, the intersection of the plane and the cone is given by
r  =  p + ercos( q)
r - ercos(q)  =  p
r( 1 - ecos(q) )  =  p
which results in
r  p
1-ecos( q)
(6)
 

As a result, z = ± r and cylindrical coordinates implies that parameterization of the conic itself is
r(q) =
 pcos( q)
1-ecos( q)
,  psin(q)
1-ecos( q)
,  p
1-ecos( q)
where we use the vector-valued funtion r since its length is the spherical coordinate distance r.      

 

EXAMPLE 7    Find the projection of the conic with eccentricity e = 1 and parameter p = 4. What type of conic is it? What is the parameterization of the conic itself?       

Solution: The projection is given by (6) with e = 1 and p = 4:
r =  4
1-cos( q)
This is a parabola with parameter p = 4. It is parameterized by
r(q) =
 4cos( q)
1-cos( q)
,  4sin( q)
1-cos( q)
,  4
1-cos( q)
which is shown below:

LiveGraphics3d Applet

       

Conic projections of the form (6) are symmetric about the x-axis. Arbitrary conic projections follow from the intersection of the cone with an arbitrary plane, which is given by z = ax+by+p with a,b, and p constant.      

 

EXAMPLE 8    Find the projection of the conic formed by the intersection of z = 3+0.5y with the right circular cone. What type of conic is it? What is the parameterization of the conic itself?       

Solution: The intersection of z = 3+0.5y with the right circular cone r2 = z2 is given by
r = 3 + 0.5rsin( q)         Þ        r 0.5 rsin( q) = 3
which results in the projection
r  3
1-0.5sin( q)
This is an ellipse with parameter p = 3 and eccentricity e = 0.5 that is symmetric about the y-axis. Moreover, the conic itself has the parameterization
r( q) =
 3cos( q)
1-0.5sin( q)
,  3sin( q)
1-0.5sin( q)
,  3
1-0.5sin( q)
which is shown below:

LiveGraphics3d Applet