Maxwell's Equations   

Coulomb's law says that if a charge of q is located at a point r = ( x,y,z) and another charge of qj is located at a point pj, then the force between them is an inverse square field of the form
F

1
4pe0

 

qqj
|| r-p|| 2

  up
where up is the unit vector parallel to r-p and where e0 is the permittivity of free space, which satisfies

1
4pe0

= 10-7c2
where c is the speed of light in a vacuum.

In a charge cloud, there are n charges q1,¼,qn, where n is extremely large, and to each charge there corresponds an inverse square field. We often consider the charge q at r = (x,y,z) to be a test charge that can be ''moved around'' in space.

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The electric field E = F/q is the coulomb force divided by the test charge, so that E is the force per unit charge and is of the form
E

1
4pe0

n
å
j = 1 

qj
|| r-pj|| 2

  up

Suppose now that W is the boundary surface of a solid containing the entire charge cloud, then
ó
õ
ó
õ


W 
E·dS = n
å
j = 1 
4p( 

qj
4pe0

 )=  

1
e0

n
å
j = 1 
qj
However, åqj is the total charge Q of the charge cloud. Thus, Gauss' theorem says that
Flux  through  W =  

1
e0

Q
That is, we can measure the amount of charge contained within a solid by measuring the flux of the electric field through the boundary surface of the solid.

We obtain even more information by applying the divergence theorem. In particular,
Flux  through  W = ó
õ
ó
õ
ó
õ


W 
div( E) dV

1
e0

Q
However, if r( x,y,z) is the density of the charge cloud, then Q is also a triple integral.
ó
õ
ó
õ
ó
õ


W 
div( E) dV =  

1
e0

Q  = 

1
e0

ó
õ
ó
õ
ó
õ


W 
r(x,y,z) dV
That is, we have
ó
õ
ó
õ
ó
õ


W 
div( E) dV = ó
õ
ó
õ
ó
õ


W 

1
e0

r( x,y,z) dV

Finally, let's notice the triple integrals are the same regardless of the solid W (as long as it is a solid that contains the entire charge). For example, the triple integrals are the same even if W is a sphere with radius R, regardless of what R is or how large it becomes. Since arbitrary solids always produce the same integrals, the integrands must be the same, which implies that
div( E) =  

1
e0

r(x,y,z)
(3)
That is, the charge density itself is determined by calculating the divergence of the electric field it produces. Conversely, if r(x,y,z) is known, then the electric field E = áE1,E2,E3 ñ is a solution to the partial differential equation

E1
x

 

E2
y

 + 

E3
z

 =  

1
e0

r(x,y,z)

Equation (3) is important mathematically, physically, and historically, for it is the first partial differential equation in the set of 4 partial differential equations known as Maxwell's equations. Specifically, Maxwell's equations consider a charge cloud to be made up of both stationary and moving charges. The stationary charges are those that produce an electric field E( x,y,z,t) at time t and have a charge density at time t of r( x,y,z,t) . The moving charges are those that produce a magnetic field B(x,y,z,t) at time t, and each moving charge in the field is assigned a vector J( x,y,z,t) dV which indicates the direction of its motion at time t.

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The vector function J( x,y,z,t) is called the current density of the charges (since moving charges are known as currents).

Maxwell's equations describe the spatial (x,y,z) and temporal (t) dependence of the electric field E( x,y,z,t) and the magnetic field B( x,y,z,t) on the charge density r( x,y,z,t) and the current density J( x,y,z,t) . This set of 4 equations is given by
(1)
div( E) = 

1
e0

 r(x,y,z,t)
       
(2)
div( B) = 0
(3)
curl( E) = -  

B
t

(4)
curl( B) = m0J + e0m0 

E
t

where m0 is permeability of free space, which satisfies c-2 = e0m0. Equation (1) is the law we derived above, and the others follow from similar arguments with triple integrals, the divergence theorem, and Stoke's theorem, which we will explore in the next section.