Arclength and the Fundamental Form

Since the fundamental form is intrinsic to a surface, any property that can be directly derived from the fundamental form is also intrinsic to the surface. For example, suppose that r( u,v) parameterizes a surface and that r( t) = r( u( t) ,v( t) ) , t in [ a,b] , is a curve on the surface. Then the velocity of r( t) is
v = ru du
dt
 + rv dv
dt
and the square of the speed is
v·v
=
æ
è
ru du
dt
+rv dv
dt
ö
ø
· æ
è
ru du
dt
+rv dv
dt
ö
ø
=
ru·ru æ
è
du
dt
ö
ø
2

 
+2rv·ru du
dt
dv
dt
+rv·rv æ
è
dv
dt
ö
ø
2

 
=
g11 æ
è
du
dt
ö
ø
2

 
+2g12 æ
è
du
dt
ö
ø
æ
è
dv
dt
ö
ø
+g22 æ
è
dv
dt
ö
ø
2

 
Thus, the length of the curve r( t) is given by  
l = ó
õ
b

a 
g11 æ
è
du
dt
ö
ø
2

 
+2g12 æ
è
du
dt
ö
ø
æ
è
dv
dt
ö
ø
+g22 æ
è
dv
dt
ö
ø
2

 
 
  dt
(3)

which show that the length of a curve on a surface is intrinsic to that surface.

For example, the xy-plane can be parameterized in polar coordinates by
r( r,q) = á rcos( q),rsin( q) ñ
Since rr = á cos( q) ,sin(q) ñ and rq = á -rsin( q) ,cos( q) ñ , the metric coefficients of the plane in polar coordinates are g11 = rr·rr = 1, g12 = rr·rq = 0, and
g22 = rq·rq = r2sin2(q) +r2cos2( q) = r2
Consequently, (3) for a curve r(t) = r( r( t) ,q( t) ), t in [ a,b] , is given by
l = ó
õ
b

a 
æ
è
 dr
dt
ö
ø
2

 
 + r2 æ
è
 dq
dt
ö
ø
2

 
 
dt
In case of r = f( q) , q in [ a,b] , we let q = t and r = f( t) .       

EXAMPLE 3    What is the length of the curve r = e-q, q in [ 0,6p] in polar coordinates?

Solution: If we let r = e-t and let  q = t, then r'  = -e-t and q ' = 1, so that
l = ó
õ
6p

0 
  
( -e-t)2+( e-t)2 (1)2
  dt = ó
õ
6p

0 
  
e-2t+e-2t
  dt
Because e-2t+e-2t = 2e-2t, this simplifies to
l = ó
õ
6p

0 
  
2e-2t
  dt = ó
õ
6p

0 
  e-qdq = Ö2( -e-6p+1)
which is approximately l = 1.414.

The fundamental form of a sphere of radius R in spherical coordinates is
ds2 = R2df2+R2sin2( f) dq2
Thus, if r( t) = Rer( f( t) ,q( t) ) , t in [ a,b], is a curve on the sphere, then its length is
l = ó
õ
b

a 
R2 æ
è
df
dt
ö
ø
2

 
 + R2sin2(f) æ
è
dq
dt
ö
ø
2

 
 
  dt
(4)
In case of f = g( q) , q in [ a,b] , we let q = t and f = g( t) .        

EXAMPLE 4    What is the length of the curve r( t) = 2Ö2er( p/4,t) , t in [ 0,p/2] , which is an arc at a constant 45° latitude between the points P( 2,0,2) and Q(0,2,2) on the sphere of radius 2Ö2 centered at the origin?
image
 Solution: Since f = p/4 and q = t, the arclength formula (4) becomes
l
=
ó
õ
p/2

0 

( 2Ö2) 2 æ
è
 d
dt
 p
4
ö
ø
2

 
+( 2Ö2) 2sin2 æ
è
 p
4
ö
ø
æ
è
 d
dt
t ö
ø
2

 
 
dt
=
ó
õ
p/2

0 

8( 0) 2+8 æ
è
 1
Ö2
ö
ø
2

 
( 1) 2
 
dt
=
ó
õ
p/2

0 
Ö4dt
=
p

Check your Reading: Is arclength an intrinsic property of a surface?