Arclength and the Fundamental Form
Since the fundamental form is intrinsic to a surface, any property
that can be directly derived from the fundamental form is also intrinsic to
the surface. For example, suppose that r( u,v)
parameterizes a surface and that r( t) = r( u( t) ,v( t) ) , t in [ a,b] , is a curve on the surface. Then the velocity of r( t) is
and the square of the speed is
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æ è
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ru |
du
dt
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+rv |
dv
dt
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ö ø
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· |
æ è
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ru |
du
dt
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+rv |
dv
dt
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ö ø
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ru·ru |
æ è
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du
dt
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ö ø
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2
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+2rv·ru |
du
dt
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dv
dt
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+rv·rv |
æ è
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dv
dt
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ö ø
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2
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| g11 |
æ è
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du
dt
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ö ø
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2
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+2g12 |
æ è
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du
dt
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ö ø
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æ è
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dv
dt
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ö ø
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+g22 |
æ è
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dv
dt
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ö ø
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2
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Thus, the length of the curve r( t) is given by
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l = |
ó õ
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b
a
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g11 |
æ è
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du
dt
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ö ø
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2
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+2g12 |
æ è
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du
dt
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ö ø
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æ è
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dv
dt
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ö ø
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+g22 |
æ è
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dv
dt
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ö ø
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2
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dt |
| (3) |
which show that the length of a curve on a surface is intrinsic to that
surface.
For example, the xy-plane can be parameterized in polar coordinates by
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r( r,q) =
á rcos( q),rsin( q)
ñ |
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Since rr =
á cos( q) ,sin(q)
ñ and rq =
á -rsin( q) ,cos( q)
ñ , the
metric coefficients of the plane in polar coordinates are g11 = rr·rr = 1, g12 = rr·rq = 0, and
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g22 = rq·rq = r2sin2(q) +r2cos2( q) = r2 |
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Consequently, (3) for a curve r(t) = r( r( t) ,q( t) ), t in [ a,b] , is given by
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l = |
ó õ
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b
a
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æ è
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dr
dt
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ö ø
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2
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+ r2 |
æ è
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dq
dt
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ö ø
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2
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dt |
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In case of r = f( q) , q in [ a,b] , we let q = t and r = f( t) .
EXAMPLE 3 What is the length of the curve r = e-q, q in [ 0,6p] in polar coordinates?
Solution: If we let r = e-t and let q = t, then r' = -e-t and q ' = 1, so that
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l = |
ó õ
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6p
0
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dt = |
ó õ
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6p
0
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dt |
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Because e-2t+e-2t = 2e-2t, this simplifies to
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l = |
ó õ
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6p
0
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dt = |
ó õ
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6p
0
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e-qdq = Ö2( -e-6p+1)
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which is approximately l = 1.414.
The fundamental form of a sphere of radius R in spherical
coordinates is
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ds2 = R2df2+R2sin2( f) dq2 |
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Thus, if r( t) = Rer( f( t) ,q( t) ) , t in [ a,b], is a curve on the sphere, then its length is
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l = |
ó õ
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b
a
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R2 |
æ è
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df
dt
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ö ø
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2
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+ R2sin2(f) |
æ è
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dq
dt
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ö ø
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2
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dt |
| (4) |
In case of f = g( q) , q in [ a,b] , we let q = t and f = g( t) .
EXAMPLE 4 What is the length of the curve r( t) = 2Ö2er( p/4,t) , t in
[ 0,p/2] , which is an arc at a constant 45°
latitude between the points P( 2,0,2) and Q(0,2,2) on the sphere of radius 2Ö2 centered at the origin?
Solution: Since f = p/4 and q = t, the arclength
formula (4) becomes
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ó õ
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p/2
0
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( 2Ö2) 2 |
æ è
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d
dt
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p
4
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ö ø
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2
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+( 2Ö2) 2sin2 |
æ è
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p
4
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ö ø
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æ è
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d
dt
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t |
ö ø
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2
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dt |
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ó õ
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p/2
0
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8( 0) 2+8 |
æ è
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1
Ö2
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ö ø
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2
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( 1) 2 |
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dt |
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Check your Reading: Is arclength an intrinsic property of a
surface?