Coordinate Transformations
If a parametric surface is of the form r(u,v) =
á f( u,v) ,g( u,v),0
ñ , then it maps the uv-plane to the xy-plane. Moreover, r( u,v) induces a chart on some part of the xy-plane
and correspondingly, it maps sets in the uv-plane to sets in the xy-plane.
Thus, parametric surfaces of the form r( u,v) =
á f( u,v) ,g( u,v) ,0
ñ are
called coordinate transformations. That is, a coordinate
transformation is a mapping of the form
|
T( u,v) =
á f( u,v) ,g( u,v)
ñ |
|
and f,g are called the components of the transformation.
It follows that T maps a set S in the uv-plane to a set T(S) in the xy-plane:
If S is a region, then we use the fact that x = f( u,v) and y = g( u,v) to find the image of the boundary of S under T( u,v) .
EXAMPLE 1 Find T( S) when T( u,v) =
á uv,u2-v2
ñ and S is the unit square in the uv-plane (i.e., S = [ 0,1] ×[0,1] ).
Solution: To find the boundary of T( S) in the xy-plane, we
find the images under x = uv and y = u2-v2 of the lines bounding the unit square in the uv-plane.
| Side of Unit Square |
|
Result of T(u,v) |
|
Image in xy-plane |
| u = 0 |
|
x = 0 and y = -v2 < 0 |
|
negative y axis |
| u = 1 |
|
x = v and y = 1-v2 |
|
,y = 1-x2 |
| v = 1 |
|
x = u and y = u2-1 |
|
y = x2-1 |
| v = 0 |
|
x = 0 and y = u2 >
0 |
|
positive y axis |
As a result, T( S) is the region in the xy-plane bounded by x = 0, y = x2-1, and y = 1-x2.
EXAMPLE 2 Find T( S) when T( u,v) =
á vcos( u) ,vsin( u)
ñ
and S is the region given by
Solution: When v = 0, then T( u,v) =
á0,0
ñ . Thus, the u-axis is mapped to the origin. When v = sin( u) , then
|
T( u,v) =
á sin( u) cos( u),sin2( u)
ñ |
|
However, x = sin( u) cos( u) , y = sin2(u) implies that
|
x2 |
= |
sin2( u) cos2( u) |
|
= |
sin2( u) ( 1-sin2( u) ) |
|
= |
y( 1-y) |
|
That is, x2 = y-y2, which is the same as x2+y2-y = 0. Completing
the square leads to
Thus, the image of v = sin( u) is the circle of radius 1/2
centered at ( 0,1/2) .
Check your Reading: Is the entire u-axis mapped to 0 by
T( u,v) =
á vcos( u) ,vsin(u)
ñ ?