EXAMPLE 5 Find ¶w/¶u and ¶w/¶v when w = x2+xy and x = u2v, y = uv2.
Solution: To begin with, the first partial derivatives of w = x2+xy are
while the partial derivatives of x and y with respect to u are
As a result, the chain rule says that
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¶w
¶u
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= ( 2x+y) |
¶x
¶u
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+x |
¶y
¶u
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Substitution for x, y and their derivatives yields
To evaluate ¶w/¶v, we substitute the first
partial derivatives to obtain
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¶w
¶v
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= ( 2x+y) |
¶x
¶v
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+x |
¶y
¶v
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The partial derivatives of x and y with respect to v are
so that substitution for x, y and their derivatives yields