Part 1: Vectors in the Plane
Now that we have studied calculus in a 2 dimensional setting, our next step
is to extend calculus to 3 or more dimensions. However, a slope
allows only a rise and a run, and as a result, slope is inherently a two dimensional
concept. Thus, we begin with a concept that is the same across any number of
dimensions -- the concept of a vector.
Given two points P1( x1,y1) and P2(x2,y2) in the xy-plane, we define the vector between them to
be
 |

|
 |
|
v = |
P1P2
|
= áx2-x1,y2-y1
ñ |
|
| (1) |
The points P1 and P2 are called, respectively, the initial
point and the terminal point of the vector v, and v is often represented by an arrow beginning at a point P1 and ending
at P2.
In general, a scalar is a number such as 1, p, or 9.28, and a 2-dimensional vector is a grouping
of two scalars a and b in the form v =
áa,b
ñ. The scalars a and b are known as the components of v =
á a,b
ñ .
EXAMPLE 1 Find the vector u with initial point P1( 2,4) and final point P2( 5,6) .
Solution: To find u, we apply (1) in
the form
 |
 |
 |
|
u = |
P1P2 |
=
á 5-2,6-4
ñ =
á 3,2
ñ |
|
EXAMPLE 2 Find the vector w with initial point P1( 9,4) and final point P2( 12,6) .
Solution: To do so, we apply (1) in the form
 |
 |
 |
|
w = |
P1P2 |
á 12-9,6-4
ñ =
á 3,2
ñ |
|
Notice that the vectors u and w in examples
1 and 2 are the same, as is further illustrated in the figure below:
That is, the translation of a vector results in the same vector,
just as the translation of a line results in a line with the same slope as
the original.
A 2-dimensional vector v =
áa,bñ can also be
defined in terms of a magnitude ||v|| and a direction angle a using trigonometric
relationships:
We say that v =
á || v|| cos(a), || v|| sin( a)
ñ is the polar form of v. The Pythagorean theorem says that
|
||v|| = |
 |
|
|
a2 + b2 |
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|
|
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and the quantity cos(a) = a / ||v|| is called a direction cosine of v.
EXAMPLE 3 What is the magnitude and direction angle of
Solution: The magnitude is
|
||v|| = |
 |
|
|
32 + 22 |
|
= |
 |
|
|
13 |
|
|
The direction angle follows from the direction cosine:
|
cos(a) = |
| 3
|
|
|
 |
|
| 13 |
|
|
, so a = cos-1 |
æ ç
è
|
| 3
|
|
|
 |
|
| 13 |
|
|
|
ö ÷
ø
|
= 0.588 radians |
|
In degree measure, the direction angle is
|
a = 0.588 radians · |
æ è
| |
|
ö ø
|
= 33.6899° |
|
to 4 decimal places.
It follows that vectors with the same direction angle are parallel and that
vectors with the same magnitude and direction are
Check your reading: How does a slope differ from a vector?