Part 1: Vectors in the Plane

Now that we have studied calculus in a 2 dimensional setting, our next step is to extend calculus to 3 or more dimensions. However, a slope allows only a rise and a run, and as a result, slope is inherently a two dimensional concept. Thus, we begin with a concept that is the same across any number of dimensions -- the concept of a vector.

Given two points P1( x1,y1) and P2(x2,y2) in the xy-plane, we define the vector between them to be

v =

P1P2

 =  áx2-x1,y2-y1 ñ
(1)

The points P1 and P2 are called, respectively, the initial point and the terminal point of the vector v, and v is often represented by an arrow beginning at a point P1 and ending at P2.

In general, a scalar is a number such as 1, p, or 9.28, and a 2-dimensional vector is a grouping of two scalars a and b in the form v = áa,b ñ.  The scalars a and b are known as the components of v = á a,b ñ .       

EXAMPLE 1    Find the vector u with initial point P1( 2,4) and final point P2( 5,6) .

Solution: To find u, we apply (1) in the form
u =   P1P2   = á 5-2,6-4 ñ = á 3,2 ñ

       

EXAMPLE 2    Find the vector w with initial point P1( 9,4) and final point P2( 12,6) .

Solution: To do so, we apply (1) in the form
w =   P1P2   á 12-9,6-4 ñ = á 3,2 ñ

Notice that the vectors u and w in examples 1 and 2 are the same, as is further illustrated in the figure below:

That is, the translation of a vector results in the same vector, just as the translation of a line results in a line with the same slope as the original. 


      

A 2-dimensional vector v = áa,bñ can also be defined in terms of a magnitude ||v|| and a direction angle a using trigonometric relationships:
 
a = || v|| cos( a)
b = || v|| sin( a)
       
We say that v = á || v|| cos(a), || v|| sin( a) ñ is the polar form of v.  The Pythagorean theorem says that
||v|| =  

a2 + b2

   
and the quantity cos(a) = a / ||v|| is called a direction cosine of v.          

EXAMPLE 3    What is the magnitude and direction angle of
v = á 3,2 ñ

Solution: The magnitude is
||v|| =  

32 + 22

  =  

13

The direction angle follows from the direction cosine:
cos(a) =   
3
13
,   so a = cos-1 æ
ç
è
3
13
  ö
÷
ø
 = 0.588 radians
In degree measure, the direction angle is
a = 0.588 radians  · æ
è
180°
p radians
ö
ø
 = 33.6899°
to 4 decimal places.

It follows that vectors with the same direction angle are parallel and that vectors with the same magnitude and direction are

 

Check your reading: How does a slope differ from a vector?